直接上代码。
主要的思路是：1.复制节点添加到最后。2.移动left值。3.删除前面多余的节点，重置left值。
代码
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| <!doctype html>
<html>
<head>
<meta charset="utf-8">
<title></title>
</head>
<style type="text/css">
*{ margin: 0; padding:0;}
li{ list-style: none; }
div{ margin: 0 auto; width: 350px; height:60px; }
ul{ position: absolute; left: 0; }
</style>
<body>
<div>
<input type="button" value="<<<<<<<<<<" id="input1" />
<input type="button" value=">>>>>>>>>>" id="input2" />
</div>
<div id="div1">
<ul id="ul1">
<li>1</li>
<li>2</li>
<li>3</li>
<li>4</li>
<li>5</li>
</ul>
</div>
</body>
<script>
var oInput1 = document.getElementById('input1');
var oInput2 = document.getElementById('input2');
var oDiv = document.getElementById('div1');
var oUl1 = document.getElementById('ul1');
var aLi = document.getElementsByTagName('li');
var onSize = aLi[0].offsetWidth + 10;
var startMove = true;
function getWidth(){
oUl1.style.width = aLi.length * onSize + 'px';
}
getWidth()
//剪切节点 不适用于本例子
/*oInput1.onclick = function(){
oUl1.appendChild(aLi[0]);
}
oInput2.onclick = function(){
oUl1.insertBefore(aLi[aLi.length-1],aLi[0]);
}*/
//复制节点 cloneNode(boolean) : true:同时复制所有子节点 flase:只复制当前节点
var iNum = 4;
oInput1.onclick = function(){
if(startMove){
startMove = false;
oUl1.style.transition = "1s";
for(var i=0;i<iNum;i++){
var oLi = aLi[i].cloneNode(true);
oUl1.appendChild(oLi);
getWidth();
}
oUl1.style.left = -i*onSize + 'px';
setTimeout(function(){
oUl1.style.transition = "0s";
for(var i=0;i<iNum;i++){
oUl1.removeChild(aLi[0]);
}
oUl1.style.left = 0;
startMove = true;
},1000)
}
}
var colors = ['red','blue','yellow','green','orange','red','pink','red','blue','orange','green'];
for(var i=0;i<aLi.length;i++){
aLi[i].style.background = colors[parseInt(Math.random()*10)]
}
</script>
</html>
|